perhitungan IS-LM
Diketahui
C = 40 + 0,6Y
I= 80-4r
M =200
Lt= 0,25Y
Lj = 0,15Y
L2 = 160-4r
jawab :
Is= Y =100 + 10r
Lm: Y= 300 - 10r
mencari nilai Y
is = lm
100 + 10r = 160 - 10r
10r + 10r = 300 - 100
20r = 200
r = 10
mencari nilai Y
is = lm
100 + 10r = 160 - 10r
10r + 10r = 300 - 100
20r = 200
r = 10
•Y*
=100+10r → 200
Y* =100+10 (10) → 200
Y* =100+10 (10) → 200
•C*
= 40 + 0,6 (200) = 160
•S*
= Y –c = 200-160 = 40
•Lt=
0,25 (200) = 50
•Lj =
0,15Y = 30
•L2
= 160-4 (10) = 120
*Hasil perhitungan diatas menunjukan syarat keseimbangan pasar barang : I=S yaitu 40
Syarat keseimbangan pasar uang Lt+Lj+L2 = M yaitu 200
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